Java代码案例27——分支判断是否做核酸

// Java分支判断是否做核酸,用或者||连接多个条件
// 每周一、四、六常态化核酸
package xiangmu;
public class Ceshi {
    public static void main(String args[]) {
        int xingqi = 6;
        if(xingqi == 1 || xingqi == 4 || xingqi == 6) {
            dayin("今天做核酸");
        }else {
            dayin("今天不做核酸");
        }
    }
    public static void dayin(String zifuchuan) {
        System.out.println(zifuchuan);
    }
}
今天做核酸